Dhruv Jurel performed well in the four-day match against South Africa. It is true that he scored unbeaten centuries in two consecutive innings. But despite this, he doesn’t seem to be in Team India’s playing XI against South Africa. No, we are not saying this. Rather, former Indian cricketer Suresh Raina has said this about wicketkeeper-batsman Jurrell.
Not Jurel, Pant will be the first wicketkeeper – Raina
Suresh Raina discussed Dhruv Jurel’s place in the team on a Star Sports show. When asked about this, his direct answer was that Rishabh Pant will be the first wicketkeeper. The anchor then asked Raina if he could play as a batsman. Raina then elaborated on the entire combination, but Dhruv Jurrell, who scored two consecutive centuries, did not fit into his combination.
Difficult to play even as a batsman
According to Suresh Raina, Team India’s top order in Tests is already set, including Shubman Gill and batsmen like Yashaswi, Sai Sudarshan and KL Rahul. Next is Rishabh Pant, followed by Ravindra Jadeja, Washington Sundar and Akshar Patel.
The first Test match between India and South Africa will be played at Eden Gardens. Suresh Raina said that considering the nature of the Eden pitch, India will definitely field three spinners, one of whom could be Kuldeep Yadav. In that case, Akshar Patel may be left out. However, Dhruv Jurrell does not look fit in the squad for the first Test against South Africa. Suresh Raina’s comments clearly indicate that Dhruv Jurrell is part of India’s 15-man squad for the Test series against South Africa. However, despite scoring two back-to-back centuries against South Africa A, a place in the playing XI looks unlikely.
