mi vs SRH, IPL 2025: Mumbai Indians won the fourth consecutive win on the basis of Rohit Sharma’s explosive innings and beat Sunrisers Hyderabad by 7 wickets. In the 41st match of the IPL 2025, Mumbai Indians won the toss and invited Hyderabad to bat first. The Hyderabad team was able to score only 143 runs after losing 8 wickets in 20 overs. Based on Rohit Sharma’s 70 -run innings, the Mumbai Indians lost only 3 wickets and scored 146 runs in 15.4 overs. Rohit faced 46 balls, with Six Sixers and 8 fours. Apart from this, Suryakumar Yadav played an explosive innings of 40 off 19 balls off 19 balls and two sixes in 19 balls. For Mumbai, Ryan Raiselton 11, Will Jack 22 and Tilak Verma did not make two. In B Ling Ling, Deepak Chahar took two for Mumbai, Bolt 4, Bumrah and captain Hardik Pandya took one wicket.
The ‘class’ of Classen could not even win Hyderabad
Sunrisers Hyderabad did not start well. Travis was out on the score of the Head Bay’s team. The team then got another blow to the 9th score as Ishaan Kishan. Then when the team’s score was 13 runs, Abhishek Sharma was fired for only 8 runs. The team suffered a fourth shock as Nitish Reddy. While the team’s score was only 35 runs, Aniket Verma was shocked at the time. But then the wicketkeeper Klasan not only crossed his team by 100 runs, but also brought the respectable score to 143. Classon scored 71 off 44 balls with 9 fours and two sixes. For Hyderabad, Abhinav Manohar scored 43 off 37 balls with the help of 2 fours and 3 sixes.
Long jumps in Mumbai’s points table
With a 7 -Wiket win against Hyderabad, Mumbai Indians have also made a strong comeback in the points table. After winning 5 matches, Mumbai has reached third with 10 points. This is the fifth and consistent win in Mumbai in IPL 2025.